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x^2+106x+600=0
a = 1; b = 106; c = +600;
Δ = b2-4ac
Δ = 1062-4·1·600
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8836}=94$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(106)-94}{2*1}=\frac{-200}{2} =-100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(106)+94}{2*1}=\frac{-12}{2} =-6 $
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